jueves, 22 de septiembre de 2016
Divisibility Criteria
Mathematics (Bilingual)
2º ESO (UNIT 1)
Divisibility
Criteria:
Divisible
by 2
A
number is divisible by 2 if the last digit is 0, 2, 4, 6 or 8.
Example:
2 346 is divisible by 2 because the last
digit is 6.
Divisible
by 3
A
number is divisible by 3 if the sum of the digits is divisible by 3.
Example:
23 457 is divisible by 3 because the sum
of the digits is 21 (2+3+4+5+7=21), and 21 is
divisible
by 3.
Divisible
by 4
A
number is divisible by 4 if the number formed by the last two digits
is either 00 or divisible by 4.
Example:
24 516 is divisible by 4 because 16 is
divisible by 4.
Divisible
by 5
A
number is divisible by 5 if the last digit is either 0 or 5.
Example:
9 876 345 is divisible by 5 because the
last digit is 5.
Divisible
by 6
A
number is divisible by 6 if it is divisible by 2 (the last digit is
0, 2, 4, 6 or 8) and it is also
divisible
by 3 (the sum of the digits is divisible by 3)
Example:
534 is divisible by 6 because is divisible
by 2 (the last digit is 4) and it is divisible by 3 (the sum of the
digits 5+3+4=12 is divisible by 3)
Divisible
by 10
A
number is divisible by 10 if the last digit is 0.
Example:
12 345 890 is divisible by 10 because the
last digit is 0.
Divisible
by 11
To
check if a number is divisible by 11, sum the digits in the odd
positions counting from the left (the first, the third, …) and then
sum the remainder digits. If the difference between the sums is
either 0 or divisible by 11, then so is the original number.
Examples:
145 879 635 918 291
Digits
in odd positions: 1+5+7+6+5=24 Digits in odd positions: 9+8+9=26
Digits
in even positions: 4+8+9+3=24 Digits in even positions: 1+2+1=4
The
difference is 24-24=0 The difference: 26-4=22
So
145 879 635 is divisible by 11. So 918 291 is divisible by 11.
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